A uniform flexible chain of mass m and length 2ℓ hangs in equilibrium over a smooth horizontal pin of negligible diameter. One end of the chain slips over the pin. The speed of chain when it leaves pin is
A
√2gℓ
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B
√gℓ
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C
√4gℓ
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D
√3gℓ
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Solution
The correct option is B√gℓ Decrease in PE= increase in KE K=mg(l−l2)⇒12mv2=mgl2⇒v=√gl