A uniform L shaped rod each of side A is held as shown in the figure- The angle - such that rod remains stable will be-

The correct option is A tan^ 1 ( 1 / 3 ) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Special Integrals - 1

A uniform L s...

Question

A uniform L shaped rod each of side A is held as shown in the figure. The angle $θ$ such that rod remains stable will be.

{tan}^{- 1} (\frac{1}{3})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{cos}^{- 1} (\frac{1}{3})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{tan}^{- 1} 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{tan}^{- 1} 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ${tan}^{- 1} (\frac{1}{3})$

Suggest Corrections

Similar questions

Q. A vertical pole subtends an angle

t a n^{- 1} (1 / 2)

at a point P on the ground. The angle subtended by the upper half of the pole at the point P is

$T w o b l o c k s o f m a s s 4 k g a n d 2 k g a r e p l a c e d s i d e b y s i d e o n a s m o o t h h o r i z o n t a l s u r f a c e a s s h o w n i n t h e f i g u r e . A h o r i z o n t a l f o r c e o f 20 N i s a p p l i e d o n 4 k g b l o c k . F i n d t h e a c c e l e r a t i o n o f e a c h b l o c k .$

Q. Show that

t a n^{- 1} \frac{1}{2} + t a n^{- 1} \frac{2}{11} + t a n^{- 1} \frac{4}{3} = \frac{π}{2}

In Young’s double slit experiment, the slits are horizontal. The intensity at a point P as shown in figure is $\frac{3}{4} I_{0}$ , where $I_{0}$ is the maximum intensity. Then the value of $θ$ is

Q. Prove that:

{tan}^{- 1} \frac{1}{5} + {tan}^{- 1} \frac{1}{7} + {tan}^{- 1} \frac{1}{3} + {tan}^{- 1} \frac{1}{8} = \frac{π}{4}

Join BYJU'S Learning Program

A uniform L shaped rod each of side A is held as shown in the figure. The angle θ such that rod remains stable will be.

The correct option is A tan−1(13)

A uniform L shaped rod each of side A is held as shown in the figure. The angle $θ$ such that rod remains stable will be.

The correct option is A ${tan}^{- 1} (\frac{1}{3})$