Question

A uniform ladder of mass 10 kg leans against a smooth wall making an angle of ${53}^o$ with it. The other end rests on a rough horizontal floor. The frictional force exerted by floor on the ladder is nearly

Answer 1

$F_r=N_2$

$N_1=Mg$

$N_2\cdot l\sin {37}^0=Mg\frac{l}{2}\cos {37}^0$

$N_2\cdot l\frac{3}{5}=Mg\frac{l}{2}\cdot \frac{4}{5}$

$N_2=\frac{2Mg}{3}=F_r$