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Standard XII

Physics

Circular Kinematics

A uniform mag...

Question

A uniform magnetic field $B = B_{0}^j$ exists in space. A particle of mass m and charge q is projected towards negative X-axis with speed v from a point (d,0,0). The maximum value of v for which the particle does not hit the y-z plane is

\frac{2 B q}{d m}

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\frac{B q d}{m}

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\frac{B q}{2 d m}

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\frac{B q d}{2 m}

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Solution

The correct option is B $\frac{B q d}{m}$
$r ⩽ d$ (does not hit the plane)
$\frac{m v}{q B} ⩽ d$
$V ⩽ \frac{q B d}{m}$
Vmax $= \frac{q B d}{m}$

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A uniform magentic field exists in space. A particle of mass m and charges q is projected towards negative x-axis with speed v from a point (d, 0, 0). The maximum value of v for which the particle does not hit the y-z plane is

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A uniform magnetic field B=B0^j exists in space. A particle of mass m and charge q is projected towards negative X-axis with speed v from a point (d,0,0). The maximum value of v for which the particle does not hit the y-z plane is

The correct option is B Bqdmr⩽d (does not hit the plane)mvqB⩽dV⩽qBdmVmax=qBdm

A uniform magnetic field $B = B_{0}^j$ exists in space. A particle of mass m and charge q is projected towards negative X-axis with speed v from a point (d,0,0). The maximum value of v for which the particle does not hit the y-z plane is

The correct option is B $\frac{B q d}{m}$
$r ⩽ d$ (does not hit the plane)
$\frac{m v}{q B} ⩽ d$
$V ⩽ \frac{q B d}{m}$
Vmax $= \frac{q B d}{m}$