A uniform magnetic field of $0.20 \times 10^{- 3}$ exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.

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Solution

$B = - \frac{d v}{d ℓ} \Rightarrow d v = - B d ℓ = - 0.2 \times 10^{- 3} \times 0.5 = - 0.1 \times 10^{- 3} T - m$
Since the sigh is -ve therefore potential decreases.

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A uniform magnetic field of 0.20×10−3 exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.

B=−dvdℓ⇒dv=−B dℓ=−0.2×10−3×0.5=−0.1×10−3T−mSince the sigh is -ve therefore potential decreases.

A uniform magnetic field of $0.20 \times 10^{- 3}$ exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.

$B = - \frac{d v}{d ℓ} \Rightarrow d v = - B d ℓ = - 0.2 \times 10^{- 3} \times 0.5 = - 0.1 \times 10^{- 3} T - m$
Since the sigh is -ve therefore potential decreases.