A uniform magnetic field of magnitude 0.20 T exists in space from east to west. With what speed should a particle of mass 0.010 g and having a charge $1.0 \times 10^{- 5} C$ be projected from south to north so that it moves with a uniform velocity ?

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Solution

$B = 0.2 T,$

$q = 1.0 \times 10^{- 5} C,$

$m = 0.01 g = 1 \times 10^{- 5} k g$

Force due to magnetic field = Gravitational force of attraction

So, $q V B = m g$

$\Rightarrow 1 \times 10^{- 5} V \times 10^{- 1} = 1 \times 10^{- 5} \times 9.8$

$V = 4.9 \times 10 = 49 m / s$

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A uniform magnetic field of magnitude 0.20 T exists in space from east to west. With what speed should a particle of mass 0.010 g and having a charge 1.0×10−5 C be projected from south to north so that it moves with a uniform velocity ?

B=0.2 T, q=1.0×10−5 C, m=0.01 g=1×10−5 kg Force due to magnetic field = Gravitational force of attraction So, qVB=mg ⇒ 1×10−5 V×10−1=1×10−5×9.8 V=4.9×10=49m/s

A uniform magnetic field of magnitude 0.20 T exists in space from east to west. With what speed should a particle of mass 0.010 g and having a charge $1.0 \times 10^{- 5} C$ be projected from south to north so that it moves with a uniform velocity ?

$B = 0.2 T,$

$q = 1.0 \times 10^{- 5} C,$

$m = 0.01 g = 1 \times 10^{- 5} k g$

Force due to magnetic field = Gravitational force of attraction

So, $q V B = m g$

$\Rightarrow 1 \times 10^{- 5} V \times 10^{- 1} = 1 \times 10^{- 5} \times 9.8$

$V = 4.9 \times 10 = 49 m / s$