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Standard XII

Physics

Time Period Independent of Amplitude

A uniform mag...

Question

A uniform magnetic field of magnitude 0.20 T exists in space from east to west. A particle having mass $10^{- 5} k g$ and charge $10^{- 5} C$ is projected from south to north so that it moves with a uniform velocity, find velocity? $(g = 10 m / s^{2})$

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Solution

Magnetic force = gravitational force

$q v B = m g$

$v = \frac{m g}{q B}$

$= \frac{10^{- 5} \times 10}{10^{- 5} \times 0.20}$

$= 50 m / s$

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A uniform magnetic field of magnitude 0.20 T exists in space from east to west. A particle having mass 10−5kg and charge 10−5C is projected from south to north so that it moves with a uniform velocity, find velocity?(g=10m/s2)

Magnetic force = gravitational force qvB=mg v=mgqB =10−5×1010−5×0.20 =50m/s

A uniform magnetic field of magnitude 0.20 T exists in space from east to west. A particle having mass $10^{- 5} k g$ and charge $10^{- 5} C$ is projected from south to north so that it moves with a uniform velocity, find velocity? $(g = 10 m / s^{2})$

Magnetic force = gravitational force

$q v B = m g$

$v = \frac{m g}{q B}$

$= \frac{10^{- 5} \times 10}{10^{- 5} \times 0.20}$

$= 50 m / s$