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Standard XII

Physics

Electric Field

A uniform mag...

Question

A uniform magnetic field $\to B = B_{0}^j$ exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point $(d, 0, 0)$ . The maximum value v for which the particle does not hit y-z plane is?

\frac{2 B q}{d m}

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\frac{B q d}{m}

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\frac{B q}{2 d m}

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\frac{B q d}{2 m}

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Solution

The correct option is B $\frac{B q d}{m}$
A uniform magnetic field $B = B 0 j$ exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point $(d, 0, 0) .$ The maximum value v for which the particle does not hit y-z plane is $F_{c e n t r i} = q v B$
$\frac{m v^{2}}{r} = q v B$
$v = \frac{B q d}{m}$

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A uniform magnetic field →B=B0^j exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point (d,0,0). The maximum value v for which the particle does not hit y-z plane is?

The correct option is B BqdmA uniform magnetic field B=B0j exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point (d,0,0). The maximum value v for which the particle does not hit y-z plane is Fcentri=qvBmv2r=qvBv=Bqdm

A uniform magnetic field $\to B = B_{0}^j$ exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point $(d, 0, 0)$ . The maximum value v for which the particle does not hit y-z plane is?