A uniform metal disc of radius R is taken and out of it a disc of diameter R is cut off from the end. The centre of mass of the remaining part will be
A
R4 from the centre
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B
R3 from the centre
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C
R5 from the centre
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D
R6 from the centre
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Solution
The correct option is DR6 from the centre Centre of mass of complete disc should lie at point O. C1 is the position of centre of mass of reminaing portion and C2 the position of centre of mass of the removed disc.
∴x (Area of remiaing portion ) =R2 (Area of removed disc) ∴x[πR2−πR24]=R2[πR24] ∴x=R6