A uniform meter rule balances horizontally on a knife-edge placed at the $60 c m$ mark when a weight of $1 g$ is suspended from one end. What is the weight of the rule?

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Solution

make a meter scale and on the last end place the weight of $20 g f$ .

At 58 cm mark the fulcrum and at $50 c m$ mark the weight of scale (downward direction both can be depicted by arrows.

a sum of anticlockwise force= sum of the clockwise force

hence let the weight of meter-scale be $x$

$x \times$ distance from fulcrum( here 8 cm) $= 20 \times 42$

$x = 105 g f$

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