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Torque about a Point

A uniform met...

Question

A uniform meter scale balances at the $40 c m$ mark when weights of $10 g$ and $20 g$ are suspended from the $10 c m$ and $20 c m$ marks. The weight of the metre scale is

A

50 g

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B

60 g

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C

10 g

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D

80 g

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Solution

The correct option is C $10 g$

Sum of moments anti clockwise $= 100 + 40$
Sum of moments clockwise $= 50 \times w$
By principal of moments
Sum of clockwise moments $=$ Sum of anti clockwise moments
$\Rightarrow 50 \times w = 500$
$w = 10 g$
Weight of meter scale $= 10 g$ .

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