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Question

A uniform meter scale balances at the 40 cm mark when weights of 10 g and 20 g are suspended from the 10 cm and 20 cm marks. The weight of the metre scale is

A
50 g
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B
60 g
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C
10 g
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D
80 g
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Solution

The correct option is C 10 g

Sum of moments anti clockwise =100+40
Sum of moments clockwise =50×w
By principal of moments
Sum of clockwise moments = Sum of anti clockwise moments
50×w=500
w=10g
Weight of meter scale =10g.

1238017_1189580_ans_357d06b65fc6468da02a0f163a2bff33.jpg

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