CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Torque

A uniform met...

Question

A uniform metre rule is pivoted at its mid - point. A weight of 50 gf is suspended at one end of it. Where should a weight of 100 gf be suspended to keep the rule horizontal ?

Open in App

Solution

Let 'a' is the distance from the centre where 100 gf (gram force) is suspended. From the principle of moments,
50gf × (L/2) = 100gf × a
a = L/4
Length of rule is 1 metre. So, a = 0.25m

Suggest Corrections

thumbs-up

15

Similar questions

Q. A uniform rule is pivoted at its mid point. A weight of

50 g f

is suspended at one end of it. Where should a weight of

100 g f

be suspended, to keep the rule horizontal?

Q. A uniform meter rule is pivoted at its mid-point. A weight of

50 g f

suspended at one end of it. Where should a weight of

100 g f

be suspended to keep the rule horizontal :

Q. A uniform ruler is pivoted at its mid point. A weight of

50 g f

is suspended at one end of it. Where should a weight of

100 g f

be suspended, to keep the ruler horizontal?

Q. A uniform metre rule balances horizontally on a knife edge placed at the

58 c m

mark when a weight of

20 g f

is suspended from one end. What is the weight of the rule?

Q. A uniform meter rule balances horizontally on a knife edge placed at the

58

cm mark when a weight of

20

gf is suspended from one end.

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Standard X Physics

Join BYJU'S Learning Program

CrossIcon