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Standard XII

Physics

Gravitational Force

A uniform met...

Question

A uniform metre rule of mass $100 g$ is balanced on a fulcrum at mark $40 c m$ by suspending an unknown mass $m$ at the mark $20 c m$ . What is the resultant moment now?

250 g f \times c m

(anticlockwise).

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500 g f \times c m

(anticlockwise).

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250 g f \times c m

(clockwise).

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Zero

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Solution

The correct option is D Zero
The resultant moment in this case should be equal to zero, because the metre rule is balanced. This is possible only when clockwise and anticlockwise moments are exactly equal to each other.

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Similar questions

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by suspending an unknown mass

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by suspending an unknown mass

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A uniform metre rule of mass 100gf is balanced on a fulcrum at mark 40cm by suspending an unknown mass m at the mark 20 cm.

(I) Find the value of m.

(II) To which side the rule will tilt if the mass m is moved to the 10 cm mark?

(III) What is the resultant moment now?

(IIII) How can it be balanced by another mass of 50 g?

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A uniform metre rule of mass 100g is balanced on a fulcrum at mark 40cm by suspending an unknown mass m at the mark 20cm. What is the resultant moment now?

The correct option is D ZeroThe resultant moment in this case should be equal to zero, because the metre rule is balanced. This is possible only when clockwise and anticlockwise moments are exactly equal to each other.

A uniform metre rule of mass $100 g$ is balanced on a fulcrum at mark $40 c m$ by suspending an unknown mass $m$ at the mark $20 c m$ . What is the resultant moment now?

The correct option is D Zero
The resultant moment in this case should be equal to zero, because the metre rule is balanced. This is possible only when clockwise and anticlockwise moments are exactly equal to each other.