A uniform metre scale is kept in equilibrium. It is supported at the 60 cm mark and a mass M is suspended from the 90 cm mark as shown in the figure. What is the relation between the weight of the scale and the weight of mass M?
The weight of the scale is greater than that of the weight of mass M.
Let M be the load and W be the weight of the scale.
Then load arm = 90 - 60 = 30 cm
Effort arm = 60 - 50 = 10 cm
In equilibrium:
Load × Load arm = Effort × Effort arm
or M × 30 = W × 10 ⇒ W = 3 M
Hence, the weight of the scale is greater than that of the weight of mass M.