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Question

A uniform metre scale is kept in equilibrium. It is supported at the 60 cm mark and a mass M is suspended from the 90 cm mark as shown in the figure. What is the relation between the weight of the scale and the weight of mass M?


A

The weight of the scale is greater than that of the weight of mass M.

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B

The weight of the scale is lesser than that of the weight of mass M.

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C

The weight of the scale is equal to than that of the weight of mass M.

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D

The weight of the mass is zero.

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Solution

The correct option is A

The weight of the scale is greater than that of the weight of mass M.


Let M be the load and W be the weight of the scale.
Then load arm = 90 - 60 = 30 cm
Effort arm = 60 - 50 = 10 cm
In equilibrium:
Load × Load arm = Effort × Effort arm
or M × 30 = W × 10 W = 3 M
Hence, the weight of the scale is greater than that of the weight of mass M.


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