Question

A uniform metre stick of 200 g is suspended from the ceiling through two vertical strings of equal lengths fixed at the ends. A small object of mass 20 g is placed on the stick at a distance of 70 cm from the left end. Find the tensions in the two strings.

Answer 1

Taking torques about A,
$0.2g\times 50+0.02g\times 70=T_2\times 100\Rightarrow 100+14=100T_2\Rightarrow T_2=1.14N$
Now, considering vertical equilibrium,
$T_1+T_2=0.2g+0.02g\Rightarrow T_1+1.14=2+0.2=2.2\Rightarrow T_1=1.06N$