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Standard XII

Physics

Centripetal Acceleration

A uniform pla...

Question

A uniform plank leans against a cylindrical body as shown in figure. The right end of plank slides at a constant speed of v = 2m/s. If R = 1m, then angular velocity of the plank when $θ = 37^{\circ}$ is (Write upto two digits after the decimal point.)

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Solution

Instantaneous axis of rotation is as shown in the figure.
$ω = \frac{v}{\frac{R}{sin θ tan θ}} = \frac{2 \times \frac{3}{5} \frac{3}{4}}{1} = 0.9$

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A uniform plank leans against a cylindrical body as shown in figure. The right end of plank slides at a constant speed of v = 2m/s. If R = 1m, then angular velocity of the plank when θ=37∘ is (Write upto two digits after the decimal point.)

Instantaneous axis of rotation is as shown in the figure. ω=vRsinθtanθ=2×35341=0.9

A uniform plank leans against a cylindrical body as shown in figure. The right end of plank slides at a constant speed of v = 2m/s. If R = 1m, then angular velocity of the plank when $θ = 37^{\circ}$ is (Write upto two digits after the decimal point.)

Instantaneous axis of rotation is as shown in the figure.
$ω = \frac{v}{\frac{R}{sin θ tan θ}} = \frac{2 \times \frac{3}{5} \frac{3}{4}}{1} = 0.9$