a uniform plank of 5meter long and supported at its centre. aboy weighing 40kgf sits at a distance from one end of sea saw where must a girl weighing 25kgf sit on the other end of sea saw so as to balance the boy.

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Solution

Dear Student,

$mass of girl = 25 kgf mass of boy = 40 kgf For balanced condition, mass of girl \times distance of girl from sea - saw = mass of boy \times distance of boy from sea - saw 25 \times distance of girl from sea - saw = 40 \times distance of boy from sea - saw distance of girl from sea - saw = \frac{40 \times distance of boy from sea - saw}{25} If the distance of boy from sea - saw is given then you can find the distance of girl from sea - saw .$

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