A uniform plank of a see-saw is 5m long and supported at its center. A boy weighing 40kgf sits at a distance of 1.5m from one end of the see-saw whereas must a girl weighing 25kgf sit on the other end of the see-saw so as to balance the boy.

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Solution

1. Solution:
Here, in the above question, we will use the formula
Effort x effort arm = load x load arm
Given that,
effort = 25N
load = 40 N
load arm = 1m
effort arm = x
by this we can write it as,
25 x X = 40 x 1
x = 1.6m
2.Conclusion:
Hence, the distance from the other end to be placed is 1.6m

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A uniform plank of a see-saw is 5m long and supported at its center. A boy weighing 40kgf sits at a distance of 1.5m from one end of the see-saw whereas must a girl weighing 25kgf sit on the other end of the see-saw so as to balance the boy.

1. Solution:Here, in the above question, we will use the formulaEffort x effort arm = load x load armGiven that, effort = 25Nload = 40 Nload arm = 1meffort arm = xby this we can write it as,25 x X = 40 x 1 x = 1.6m2.Conclusion:Hence, the distance from the other end to be placed is 1.6m

1. Solution:
Here, in the above question, we will use the formula
Effort x effort arm = load x load arm
Given that,
effort = 25N
load = 40 N
load arm = 1m
effort arm = x
by this we can write it as,
25 x X = 40 x 1
x = 1.6m
2.Conclusion:
Hence, the distance from the other end to be placed is 1.6m