The net torque acting on the bar about P when it is made to till through a small distance x is given as,
τ=−mgxcosθ
−IPω2θ=−mgx
Since cosθ=1 for small θ so, x=Rθ for small θ.
−ml212ω2θ=−mgRθ
ω=√12gRl2
T=2πω
T=2πl√12gR
It is proved that it will execute S.H.M. with the period of 2πl√12gR.