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Question

A uniform ring of mass m is lying at a distance 1.73 a from the centre of a sphere of mass M just over the sphere where a is the small radius of the ring as well as that of the sphere. Then gravitational

force exerted is


A

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B

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C

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D

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Solution

The correct option is D


dF sin θ will get cancelled

d Fnet = dF cos θ = (dm)E cos θ

= (dm) GM32a2+(3a2)2

Fnet = d Fnet

= 38 Gmma2

mass of the earth m1 = M, Mass of the moon m2 = M81 and distance between earth & moon d = 60R


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