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Question

A uniform rod AB of mass M and length L is hinged at end A. It is released from rest at a horizontal position. The linear acceleration of the centre of mass immediately after release is

A
g
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B
g2
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C
g4
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D
3g4
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Solution

The correct option is D 3g4

Torque about A immediately after release
τ=Mg×L2Iα=MgL2
or α=MgL2I=3g2L(I=ML23)

Therefore, linear acceleration of the centre of mass, immediately after release is
aCM=L2×α=L2×3g2L=3g4

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