Question

A uniform rod of length, I = 1 m and mass, m = 2 kg is suspended with the help of two massless strings as shown in figure below. Calculate tension T (in N) in the left string at the instant when the right string snaps ($g=10m/s^2$)

• A. 5 N
• B. 7 N
• C. 3.5 N
• D. 10 N

Answer 1

The correct option is A 5 N


$Mg-T=M{a}_y....\left(i\right)$

$T\left(\frac{L}{2}\right)=\frac{M{L}^2}{12}\alpha ....\left(ii\right)$

$a_y=\frac{L}{2}\alpha .....\left(iii\right)$

on solving we get

$T=\frac{Mg}{4}=5N$