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Standard X

Physics

Torque

A uniform rod...

Question

A uniform rod of length $l$ and mass $2 m$ rests on a smooth horizontal table. A point of mass $m$ moving horizontally at right angle to the rod with velocity $v$ collides with one end of the rod and sticks to it, then

Angular velocity of the system after collision is

v / l

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Angular velocity of the system after collision is

2 v / l

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the loss in kinetic energy of the system as a whole as a result of the collision is

m v^{2} / 6

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the loss in kinetic energy of the system as a whole as a result of the collision is

m v^{2} / 24

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Solution

The correct options are
A Angular velocity of the system after collision is $v / l$
C the loss in kinetic energy of the system as a whole as a result of the collision is $m v^{2} / 6$

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A uniform rod of length l and mass 2m rests on a smooth horizontal table. A point of mass m moving horizontally at right angle to the rod with velocity v collides with one end of the rod and sticks to it, then

The correct options are A Angular velocity of the system after collision is v/l C the loss in kinetic energy of the system as a whole as a result of the collision is mv2/6

A uniform rod of length $l$ and mass $2 m$ rests on a smooth horizontal table. A point of mass $m$ moving horizontally at right angle to the rod with velocity $v$ collides with one end of the rod and sticks to it, then

The correct options are
A Angular velocity of the system after collision is $v / l$
C the loss in kinetic energy of the system as a whole as a result of the collision is $m v^{2} / 6$