You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Torque

A uniform rod...

Question

A uniform rod of length $l$ and mass $2 m$ rests on a smooth horizontal table. A point of mass $m$ moving horizontally at right angle to the rod with velocity $v$ collides with one end of the rod and sticks to it, then

Angular velocity of the system after collision is

v / l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Angular velocity of the system after collision is

2 v / l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the loss in kinetic energy of the system as a whole as a result of the collision is

m v^{2} / 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

the loss in kinetic energy of the system as a whole as a result of the collision is

m v^{2} / 24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A Angular velocity of the system after collision is $v / l$
C the loss in kinetic energy of the system as a whole as a result of the collision is $m v^{2} / 6$

Suggest Corrections

Similar questions

Q. A uniform rod of length L and mass 4m lies on a frictionless horizontal surface on which it is free to move anyway. A ball of mass m moving with speed v as shown in figure collides with the rod at one of the ends. If ball comes to rest immediately after collision with the rod then find out angular velocity

ω

of rod just after collision.

Q. Consider a uniform rod of mass

M = 4 m

and length

L

pivoted about its centre. A mass

m

moving with a velocity

V

making an angle

θ = \frac{π}{4}

to the rod's long axis collides with one end of the rod, and sticks to it. The angular speed of the rod-mass system just after the collision is:

Q. A uniform rod of length

l

and mass

4 m

lies on a frictionless horizontal surface on which it is free to move. A ball of mass

m

moving with speed

v

as shown in figure, collides with the rod at one of its ends. If the ball comes to rest immediately after the collision, then find the angular velocity

ω

of the rod just after collision.

Q. A unifonn rod of length

L

and mass

2 m

rests on a smooth horizontal table, A point mass

m

moving horizontally at right angles to the rod with velocity v collides with one end of the rod and sticks it Then

Q. A uniform rod having mass

m

and length

L

lies on a horizontal surface. A particle of mass

\frac{m}{2}

moving with speed

u

strikes the rod perpendicularly at one end and sticks to the rod as shown in the figure. Find the total angular momentum of the system about the origin just after the collision, if the angular velocity of the rod just after the collision is

ω

about its centre.

Join BYJU'S Learning Program

A uniform rod of length l and mass 2m rests on a smooth horizontal table. A point of mass m moving horizontally at right angle to the rod with velocity v collides with one end of the rod and sticks to it, then

The correct options are A Angular velocity of the system after collision is v/l C the loss in kinetic energy of the system as a whole as a result of the collision is mv2/6

A uniform rod of length $l$ and mass $2 m$ rests on a smooth horizontal table. A point of mass $m$ moving horizontally at right angle to the rod with velocity $v$ collides with one end of the rod and sticks to it, then

The correct options are
A Angular velocity of the system after collision is $v / l$
C the loss in kinetic energy of the system as a whole as a result of the collision is $m v^{2} / 6$