wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A uniform rod of mass M and length a lies on a smooth horizontal plane. A particle of mass m, moving at a speed v, perpendicular to the length of the rod strikes it at a distance a4 from the center and stops after the collision. The angular velocity of the rod about its center just after the collision is-

A
3mvMa
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
mvMa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2mv3Ma
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3mvMa

Taking Angular Momentum about the centre of mass C of the rod.
mva4=112Ma2ωω=3mvMA

flag
Suggest Corrections
thumbs-up
7
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon