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Question

A uniform rod of mass M and length l is held in position shown in the figure. Than find the potential energy of the rod

302545_c3b39519b7ac4cc2a6888793a13ef08e.png

A
U=Mgcosθl2
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B
U=Mgsinθl2
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C
U=Mgtanθl2
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D
None of these
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Solution

The correct option is B U=Mgsinθl2
dU=l0Mldx.g.x.sinθ
U=Mgsinθl2
Note that centre of mass of the rod is at height (l2sinθ) from the ground.
276268_302545_ans_a81138ae9aca422f9a141fc5689de650.png

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