Question

A uniform rod of mass 'm' and Length 'L' is rotated about its perpendicular bisector at an angular speed $\omega$. Calculate its angular momentum about its Axis of rotation?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

The situation is depicted in the figure shown,

As we know, for this rigid body,

$=\frac{M{L}^2}{12}$$\omega$ $\left|\underset{L}{\to }\right|=l\omega$

{where I = moment of Inertia of rod about its axis of rotation}