Question

A uniform rod of mass '$m$' and Length '$L$' is rotated about its perpendicular bisector at an angular speed $\omega$. Calculate its angular momentum about its Axis of rotation?

• A. $\frac{M{L}^2}{12}\omega$
• B. $\frac{2M{L}^2}{12}\omega$
• C. $\frac{32M{L}^2}{3}\omega$
• D. $\frac{M{L}^2}{24}\omega$

Answer 1

The correct option is A

$\frac{M{L}^2}{12}\omega$

The situation is depicted in the figure shown,

As we know, for this rigid body,

$|\overrightarrow{L}|$ = $I\omega$

= $\frac{M{L}^2}{12}\omega$ {where $I$ = moment of Inertia of rod about its axis of rotation}