A uniform rod of mass m and length l₀is pivoted at one end and is hanging in the vertical direction. The period of small angular oscillations of the rod is

T = 3 π \sqrt{\frac{2 l_{0}}{3 g}}

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T = 4 π \sqrt{\frac{l_{0}}{3 g}}

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T = 4 π \sqrt{\frac{2 l_{0}}{3 g}}

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T = 2 π \sqrt{\frac{2 l_{0}}{3 g}}

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Solution

The correct option is D $T = 2 π \sqrt{\frac{2 l_{0}}{3 g}}$

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A uniform rod of mass m and length l0 is pivoted at one end and is hanging in the vertical direction. The period of small angular oscillations of the rod is

The correct option is D T=2π√2l03g

A uniform rod of mass m and length l₀is pivoted at one end and is hanging in the vertical direction. The period of small angular oscillations of the rod is

The correct option is D $T = 2 π \sqrt{\frac{2 l_{0}}{3 g}}$