Question

A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is

• A. $\frac{2}{3}m{R}^2$
• B. $m{R}^2$
• C. $\frac{1}{2}m{R}^2$
• D. $2m{R}^2$

Answer 1

The correct option is D

$2m{R}^2$

$I=m{R}^2+m{R}^2=2m{R}^1$ (By parallel axis theorem)