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Question

A uniform rope of length 10 m and mass 15 kg hangs vertically from a rigid support. A block of mass 5 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.08 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope will be

A
0.08 m
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B
0.04 m
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C
0.16 m
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D
0 m
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Solution

The correct option is C 0.16 m
Wavelength at lower end is 0.08 m
Velocity of wave on string =Tμ
μ=1510=1.5
Tension at lower end T=50 N
Tension at upper end T=200 N
vlower=501.5
vupper=2001.5
frequency is constant hence v1λ1=v2λ2
500.08=200λ
λ=2×0.08
=0.16 m

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