Question

# A uniform rope of length L, resting on frictionless horizontal surface is pulled at one end by a force F. Then the tension T in the rope at a distance l from the end where the force F is applied is

A
T=F
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
T=FLL
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
T=FIL
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
T=F(11L)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D T=F(1−1L)Let tension at P be T. Imagine rope to be divided into two parts A and BMass of rope=MMass of part A=MA=MLIMass of part B=MB=ML(L−I)Let the rope move with acceleration a, then for part AF−T=MAaor F−T=MIaL...(i)For part B T−O=MBaor T=ML(L−I)a...(ii)Adding Eqs (i) and (ii) we getF=MLa(1+L−I)=MLa.L=Ma⇒a=FM....(iii)From Eqs. (i), (ii), (iii)T=ML(L−1).FM=ML(L−1)=F(1−1L)

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Circular Permutations
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program