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Question

A uniform rope of mass M and the length L hangs from a ceiling. The speed of transverse waves at a distance x from the lower end will be

A
xg
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B
(Lx)g
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C
xg/2
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D
2(1xL)Lg
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Solution

The correct option is A xg
μ is mass per unit length of rope.
At a distance x from the lower end we will find tension which will be
T=μgx
So, using v=Tμ (speed of transverse wave on a string)
v=μgxμ=gx

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