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Question

A uniform rule of weight 10 gf us pivoted at its 0 marks.
(1) What moment of force depressed the rule?
(2) How can it be made horizontal by applying the least force?

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Solution

Given that,

Weight w=10gf

(a). Moment of force = magnitude of force X perpendicular distance of the line of action of force from the axis of rotation

=50cm×10gf

=500cmgf

(b). To apply the least force we obviously have to make the perpendicular distance highest.

Hence, the least force should be applied at 100 cm mark

Thus, by principle of moments

500gfcm=100cm×F

F=5gf

Hence, the force should be 5gf upwards at the 100 cm mark


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