A uniform slender rod of length L, cross section area A and Young's modulus Y is acted upon by forces as shown in figure. If elongation of rod is $\frac{n F L}{A Y}$ , then n is (Write upto two digits after the decimal point.)

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Solution

By $Δ l = \frac{T L}{A Y} \Rightarrow Δ l_{1} = \frac{3 F}{A Y} \frac{L}{2}$ and $Δ l_{2} = \frac{4 F}{A Y} \frac{L}{2}$

$Δ l = Δ l_{1} + Δ l_{2} = \frac{7}{2} \frac{F L}{A Y}$

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A uniform slender rod of length L, cross section area A and Young's modulus Y is acted upon by forces as shown in figure. If elongation of rod is nFLAY, then n is (Write upto two digits after the decimal point.)

By Δl=TLAY⇒Δl1=3FAYL2 and Δl2=4FAYL2 Δl=Δl1+Δl2=72FLAY

A uniform slender rod of length L, cross section area A and Young's modulus Y is acted upon by forces as shown in figure. If elongation of rod is $\frac{n F L}{A Y}$ , then n is (Write upto two digits after the decimal point.)

By $Δ l = \frac{T L}{A Y} \Rightarrow Δ l_{1} = \frac{3 F}{A Y} \frac{L}{2}$ and $Δ l_{2} = \frac{4 F}{A Y} \frac{L}{2}$

$Δ l = Δ l_{1} + Δ l_{2} = \frac{7}{2} \frac{F L}{A Y}$