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Question

A uniform solid cylinder of density 0.8gm/cm2 floats in equilibrium in a combination of two non mixing liquids A and B with its axis vertical.The densities of the liquids A and B are 0.4gm/cm3 and 0.7gm/cm3, respectively. The height of liquid A is hA=1.2cm.The length of the part of the cylinder immersed in liquid B is hB=0.8cm
Find h, the length of the part of the cylinder in air.
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Solution

For equilibrium buoyant force= weight of the body
hAρAAg+hBρBAg=(hA+hA+h)AρCg
where, ρC is density of cylinder
h=[(hBρA)+hBρBρC](hA+hB)=0.25

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