  Question

# A uniform solid sphere of mass 1 kg and radius 10 cm is kept stationary on a rough inclined plane by fixing a highly dense particle at B. Inclination of plane is 37∘ with horizontal and AB is the diameter of the sphere which is parallel to the plane, as shown in figure. Calculate the mass of the particle fixed at B and the minimum coefficient of fiction. 3kg, 0.75 4 kg, 0.75 4 kg, 0.50 2 kg, 0.50

Solution

## The correct option is A 3kg, 0.75 Let assume the mass of the particle be m. let us draw the free body diagram of the system of sphere and particle. Since system is in static equilibrium, therefore, torque of forces acting on the system should be zero. Taking torque about point P of all of the forces acting on the system, R(Mg sin 37∘)+(Mg sin 37∘)R=(Mg cos 37∘)R ⇒          m=3kg Considering forces normal the plane, N = Mg cos  37∘ + mg cos  37∘ = 32 N The friction force between sphere and plane is static nature, Now considering forces along the plane,                 f= mg sin  37∘ + mg sin 37 = 24 N But  f ≤μN where μ is coefficient of friction, which gives μ≥fN or μmin = 0.75.  Suggest corrections   