wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A uniform solid sphere of radius r is rolling on a smooth horizontal surface with velocity V and angular velocity ω (where V=ωr). The sphere collides with a sharp edge on the wall as shown in the figure. The coefficient of friction between the sphere and the edge μ=1/5. Just after the collision the angular velocity of the sphere becomes equal to zero. The linear velocity of the sphere just after the collision is equal to :
120430_f33bad3a676e4b72aa5a9f2f2cc41811.png

A
V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
V5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3V5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
V6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A V
Let the velocity of sphere after the collision be V'.
Using conservation of momentum, mV+0=mV+0
V=V where -ve sign suggests that sphere will reverse its direction.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon