wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A uniform sphere of mass m is positioned between two horizontal planks A and B of mass 2 m and m respectively as shown. Ground surface is smooth and friction between planks and sphere is sufficient so that no slipping takes place. Horizontal forces F1 and F2 are applied on plank so that acceleration of sphere is zero. Plank B is moving towards right with acceleration a. Which of the following is/are correct?

A
Both planks have same acceleration
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Net force on sphere is non-zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
F1+F2=175ma
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
friction=5 ma
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C F1+F2=175ma
Since, sphere is at rest, both friction at top and bottom will be equal as acceleration of sphere is zero. Acceleration of both planks -
a1=a2=αR=a No slipping
F1f=ma ...(1)
F2f=2ma ...(2)
2fR=25mR2α
2f=25m a ...(3)
Adding equations (1), (2) and (3),
F1f+F2f+2f=m a+2ma+25m a
F1+F2=(3+25)m a=175m a
Why this question?

Tip: The condition for no slipping can be applied at all the common interfaces- watch out- you are never short of equations.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Instantaneous Axis of Rotation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon