A uniform sphere of radius R is placed on a rough horizontal surface and given a linear velocity v0 and an angular velocity -0 as shown- If the angular velocity and the linear velocity both become zero simultaneously- then

The correct option is C 5V_0=2ω_0R Considering bottom most point Vp=Vo+R #969;oIf disc drops both v and w becomes zeroAngular momentum about P is conserv ...

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Byju's Answer

Standard XII

Physics

The 'e' Equation

A uniform sph...

Question

A uniform sphere of radius R is placed on a rough horizontal surface and given a linear velocity $v_{0}$ and an angular velocity $ω_{0}$ as shown. If the angular velocity and the linear velocity both become zero simultaneously, then

V - 0 = ω_{0} R

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2 V_{0} = 5 ω_{0} R

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5 V_{0} = 2 ω_{0} R

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2 V - 0 = ω_{0} R

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Solution

The correct option is C $5 V_{0} = 2 ω_{0} R$
Considering bottom most point Vp=Vo+Rωo
If disc drops both v and w becomes zero
Angular momentum about P is conserved.
Li=mVor-Ioω0=Lfinal=0
o = Lfinal=0
therefore mvoR=Ioωo
mVoR=mR2/2 ω0
therefore 2V0=Rω0000000

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A uniform sphere of radius R is placed on a rough horizontal surface and given a linear velocity v0 and an angular velocity ω0 as shown. If the angular velocity and the linear velocity both become zero simultaneously, then

The correct option is C 5V0=2ω0RConsidering bottom most point Vp=Vo+RωoIf disc drops both v and w becomes zeroAngular momentum about P is conserved.Li=mVor-Ioω0=Lfinal=0o = Lfinal=0therefore mvoR=IoωomVoR=mR2/2 ω0therefore 2V0=Rω0000000

A uniform sphere of radius R is placed on a rough horizontal surface and given a linear velocity $v_{0}$ and an angular velocity $ω_{0}$ as shown. If the angular velocity and the linear velocity both become zero simultaneously, then

The correct option is C $5 V_{0} = 2 ω_{0} R$
Considering bottom most point Vp=Vo+Rωo
If disc drops both v and w becomes zero
Angular momentum about P is conserved.
Li=mVor-Ioω0=Lfinal=0
o = Lfinal=0
therefore mvoR=Ioωo
mVoR=mR2/2 ω0
therefore 2V0=Rω0000000