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Question

A uniform steel bar of cross-sectional area A and length L. is suspended so that it hangs vertically. The stress at the middle point of the bar is ( ρ is the density of steel)

A
L2Aρg
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B
Lρg2
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C
LAρg
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D
Lρg
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Solution

The correct option is D Lρg2
mass = density × volume. =ρAL2 stress =FA=mgA
=ρALg2A=ρLg2

2000703_1166426_ans_79c76bf4e2cd44de94a82b28d35a32fd.PNG

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