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Question

A uniform string fixed at both ends is vibrating in 3rd harmonic and equation y=4(cm) sin[(0.8cm1)×]cos[(400πs1)t]The length of the vibrating string is

A
6.75m
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B
12.45m
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C
11.8m
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D
18.7m
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Solution

The correct option is C 11.8m
y=4sin(0.8x)cos(400πt)w=400π=2πff=200Hzv=wk=400π×1000.8m/s3v2l=f200=3×400π×1002×l×0.8l=3×400π4×0.8=300π0.8cm=11.8m
Hence,
option (C) is correct answer.

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