A uniform thin bar of mass 6 m and length 12L is bent to make a regular hexagon. Its moment of inertia about an axis passing through the centre of mass and perpendicular to the plane of a hexagon is
A
20mL2
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B
6mL2
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C
125mL2
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D
30mL2
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Solution
The correct option is A20mL2 I1=m(2L)212=mL33 I1′=mL33+m(√3L)2=103mL2 Total moment of system about axis =6I=20mL2