A uniform thin consonant wire of resistance 'R' is bent like a circle. P and Q are two points on the wire such that the arc PQ subtends and angle θ at the centre. Effective resistance between P and Q is
A
Rθ4π(π−θ)
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B
Rθπ+8
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C
Rθ2π2(2π−θ)
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D
Rθ4π2(2π−θ)
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Solution
The correct option is CRθ4π2(2π−θ) R1=θ2πRR2=(1−θ2π)R