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Question

A uniform thin consonant wire of resistance 'R' is bent like a circle. P and Q are two points on the wire such that the arc PQ subtends and angle θ at the centre. Effective resistance between P and Q is

A
Rθ4π(πθ)
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B
Rθπ+8
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C
Rθ2π2(2πθ)
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D
Rθ4π2(2πθ)
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Solution

The correct option is C Rθ4π2(2πθ)
R1=θ2πRR2=(1θ2π)R

These two are in series.
Reff=(1θ2π)θ2πR×RR=(2πθ)θR4π2

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