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Standard XII

Physics

Angular Velocity

A uniform thi...

Question

A uniform thin rod of mass $M$ , length $L$ is vertically straight on a horizontal floor. If the rod is falling to a side without slipping at its bottom, the moment of inertia is:

\frac{M L^{2}}{3}

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\frac{M L^{2}}{6}

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\frac{M L^{2}}{9}

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\frac{M L^{2}}{12}

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Solution

The correct option is A $\frac{M L^{2}}{3}$
MI of a rod of length L and mass M about an axis passing through one end is,
$I = \frac{M L^{2}}{3}$
(since body is not slipping so inertia will be considered from one end of the rod)

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A uniform thin rod of mass M, length L is vertically straight on a horizontal floor. If the rod is falling to a side without slipping at its bottom, the moment of inertia is:

The correct option is A ML23MI of a rod of length L and mass M about an axis passing through one end is, I=ML23(since body is not slipping so inertia will be considered from one end of the rod)

A uniform thin rod of mass $M$ , length $L$ is vertically straight on a horizontal floor. If the rod is falling to a side without slipping at its bottom, the moment of inertia is:

The correct option is A $\frac{M L^{2}}{3}$
MI of a rod of length L and mass M about an axis passing through one end is,
$I = \frac{M L^{2}}{3}$
(since body is not slipping so inertia will be considered from one end of the rod)