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Standard XII

Physics

Moment of Inertia of a Rod

A uniform tub...

Question

A uniform tube which is closed at one end, contains a piece of mercury 8 cm long, when tube is kept vertically with closed end upward, in this condition length of air column trapped is 15 cm. If tube is turned up down so that closed end goes down. Length of trapped air column approximately is (Atmospheric Pressure = 76 cm of Hg)

12 c m

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15 c m

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20 c m

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8 c m

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Solution

The correct option is A $12 c m$

for trapped air
$P_{1} V_{1} = P_{2} V_{2}$
$68 \times 15 \times A = 84 \times l_{2} \times A$
$l_{2} = \frac{68 \times 15}{84} = 12.14 \approx 12 c m$

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The correct option is A 12 cm for trapped air P1V1=P2V2 68×15×A=84×l2×A l2=68×1584=12.14≈12 cm

The correct option is A $12 c m$

for trapped air
$P_{1} V_{1} = P_{2} V_{2}$
$68 \times 15 \times A = 84 \times l_{2} \times A$
$l_{2} = \frac{68 \times 15}{84} = 12.14 \approx 12 c m$