Question

A uniform wire ABC has a mass of $10$ $gm$. A current of $2$ $A$ flows through it. The wire is kept in a uniform magnetic field of $2$ $T$. The acceleration of the wire will be :
[Given $AB$=$4$ $cm$, $BC$=$5$ $cm$]

• A. zero
• B. 12 $m/s^2$ along y-direction
• C. 36 $m/s^2$ along x-direction
• D. 12 $m/s^2$ along z-direction

Answer 1

The correct option is B 12 $m/s^2$ along y-direction

$F$$=Bil$
$ma$ $=Bil$

As total force will be vector sum of AB and BC, the wires AB and BC can be replaced by straight wire AC as shown in the figure.

${10}^{-2}\times a=2\times 2\times 3\times {10}^{-2}$
$a=12m/s^2$ along y-direction