A uniform wire of resistance 50Ω is cut into five equal parts. These parts are now connected in parallel. Then the equivalent resistance of the combination is:
A
2Ω
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B
12Ω
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C
250Ω
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D
6250Ω
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Solution
The correct option is A2Ω We know that R∝l
On cutting the wire into five equal parts, length of each part becomes one-fifth and hence resistance of each part=R=505=10Ω
When all five wires of resistance R are connected in parallel, equivalent resistance becomes R5=105