A uniform wire of resistance $R$ and length $L$ is cut into four equal parts, each of length $\frac{L}{4}$ , which are then connected in parallel combination. The effective resistance of the combination will be

R

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4 R

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\frac{R}{4}

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\frac{R}{16}

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Solution

The correct option is C $\frac{R}{16}$
As resistance is directly proportional to length, the resistance of each part is $\frac{R}{4}$ , so when they are all connected in parallel, the resistance further becomes one-fourth. Thus, the new resistance is $\frac{R}{16}$ .

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The correct option is C $\frac{R}{16}$
As resistance is directly proportional to length, the resistance of each part is $\frac{R}{4}$ , so when they are all connected in parallel, the resistance further becomes one-fourth. Thus, the new resistance is $\frac{R}{16}$ .